Integrand size = 18, antiderivative size = 232 \[ \int \frac {(a+b x)^{5/2} (A+B x)}{x^8} \, dx=\frac {b^2 (A b-2 a B) \sqrt {a+b x}}{64 a x^4}+\frac {b^3 (A b-2 a B) \sqrt {a+b x}}{384 a^2 x^3}-\frac {5 b^4 (A b-2 a B) \sqrt {a+b x}}{1536 a^3 x^2}+\frac {5 b^5 (A b-2 a B) \sqrt {a+b x}}{1024 a^4 x}+\frac {b (A b-2 a B) (a+b x)^{3/2}}{24 a x^5}+\frac {(A b-2 a B) (a+b x)^{5/2}}{12 a x^6}-\frac {A (a+b x)^{7/2}}{7 a x^7}-\frac {5 b^6 (A b-2 a B) \text {arctanh}\left (\frac {\sqrt {a+b x}}{\sqrt {a}}\right )}{1024 a^{9/2}} \]
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Time = 0.08 (sec) , antiderivative size = 232, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.278, Rules used = {79, 43, 44, 65, 214} \[ \int \frac {(a+b x)^{5/2} (A+B x)}{x^8} \, dx=-\frac {5 b^6 (A b-2 a B) \text {arctanh}\left (\frac {\sqrt {a+b x}}{\sqrt {a}}\right )}{1024 a^{9/2}}+\frac {5 b^5 \sqrt {a+b x} (A b-2 a B)}{1024 a^4 x}-\frac {5 b^4 \sqrt {a+b x} (A b-2 a B)}{1536 a^3 x^2}+\frac {b^3 \sqrt {a+b x} (A b-2 a B)}{384 a^2 x^3}+\frac {b^2 \sqrt {a+b x} (A b-2 a B)}{64 a x^4}+\frac {(a+b x)^{5/2} (A b-2 a B)}{12 a x^6}+\frac {b (a+b x)^{3/2} (A b-2 a B)}{24 a x^5}-\frac {A (a+b x)^{7/2}}{7 a x^7} \]
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Rule 43
Rule 44
Rule 65
Rule 79
Rule 214
Rubi steps \begin{align*} \text {integral}& = -\frac {A (a+b x)^{7/2}}{7 a x^7}+\frac {\left (-\frac {7 A b}{2}+7 a B\right ) \int \frac {(a+b x)^{5/2}}{x^7} \, dx}{7 a} \\ & = \frac {(A b-2 a B) (a+b x)^{5/2}}{12 a x^6}-\frac {A (a+b x)^{7/2}}{7 a x^7}-\frac {(5 b (A b-2 a B)) \int \frac {(a+b x)^{3/2}}{x^6} \, dx}{24 a} \\ & = \frac {b (A b-2 a B) (a+b x)^{3/2}}{24 a x^5}+\frac {(A b-2 a B) (a+b x)^{5/2}}{12 a x^6}-\frac {A (a+b x)^{7/2}}{7 a x^7}-\frac {\left (b^2 (A b-2 a B)\right ) \int \frac {\sqrt {a+b x}}{x^5} \, dx}{16 a} \\ & = \frac {b^2 (A b-2 a B) \sqrt {a+b x}}{64 a x^4}+\frac {b (A b-2 a B) (a+b x)^{3/2}}{24 a x^5}+\frac {(A b-2 a B) (a+b x)^{5/2}}{12 a x^6}-\frac {A (a+b x)^{7/2}}{7 a x^7}-\frac {\left (b^3 (A b-2 a B)\right ) \int \frac {1}{x^4 \sqrt {a+b x}} \, dx}{128 a} \\ & = \frac {b^2 (A b-2 a B) \sqrt {a+b x}}{64 a x^4}+\frac {b^3 (A b-2 a B) \sqrt {a+b x}}{384 a^2 x^3}+\frac {b (A b-2 a B) (a+b x)^{3/2}}{24 a x^5}+\frac {(A b-2 a B) (a+b x)^{5/2}}{12 a x^6}-\frac {A (a+b x)^{7/2}}{7 a x^7}+\frac {\left (5 b^4 (A b-2 a B)\right ) \int \frac {1}{x^3 \sqrt {a+b x}} \, dx}{768 a^2} \\ & = \frac {b^2 (A b-2 a B) \sqrt {a+b x}}{64 a x^4}+\frac {b^3 (A b-2 a B) \sqrt {a+b x}}{384 a^2 x^3}-\frac {5 b^4 (A b-2 a B) \sqrt {a+b x}}{1536 a^3 x^2}+\frac {b (A b-2 a B) (a+b x)^{3/2}}{24 a x^5}+\frac {(A b-2 a B) (a+b x)^{5/2}}{12 a x^6}-\frac {A (a+b x)^{7/2}}{7 a x^7}-\frac {\left (5 b^5 (A b-2 a B)\right ) \int \frac {1}{x^2 \sqrt {a+b x}} \, dx}{1024 a^3} \\ & = \frac {b^2 (A b-2 a B) \sqrt {a+b x}}{64 a x^4}+\frac {b^3 (A b-2 a B) \sqrt {a+b x}}{384 a^2 x^3}-\frac {5 b^4 (A b-2 a B) \sqrt {a+b x}}{1536 a^3 x^2}+\frac {5 b^5 (A b-2 a B) \sqrt {a+b x}}{1024 a^4 x}+\frac {b (A b-2 a B) (a+b x)^{3/2}}{24 a x^5}+\frac {(A b-2 a B) (a+b x)^{5/2}}{12 a x^6}-\frac {A (a+b x)^{7/2}}{7 a x^7}+\frac {\left (5 b^6 (A b-2 a B)\right ) \int \frac {1}{x \sqrt {a+b x}} \, dx}{2048 a^4} \\ & = \frac {b^2 (A b-2 a B) \sqrt {a+b x}}{64 a x^4}+\frac {b^3 (A b-2 a B) \sqrt {a+b x}}{384 a^2 x^3}-\frac {5 b^4 (A b-2 a B) \sqrt {a+b x}}{1536 a^3 x^2}+\frac {5 b^5 (A b-2 a B) \sqrt {a+b x}}{1024 a^4 x}+\frac {b (A b-2 a B) (a+b x)^{3/2}}{24 a x^5}+\frac {(A b-2 a B) (a+b x)^{5/2}}{12 a x^6}-\frac {A (a+b x)^{7/2}}{7 a x^7}+\frac {\left (5 b^5 (A b-2 a B)\right ) \text {Subst}\left (\int \frac {1}{-\frac {a}{b}+\frac {x^2}{b}} \, dx,x,\sqrt {a+b x}\right )}{1024 a^4} \\ & = \frac {b^2 (A b-2 a B) \sqrt {a+b x}}{64 a x^4}+\frac {b^3 (A b-2 a B) \sqrt {a+b x}}{384 a^2 x^3}-\frac {5 b^4 (A b-2 a B) \sqrt {a+b x}}{1536 a^3 x^2}+\frac {5 b^5 (A b-2 a B) \sqrt {a+b x}}{1024 a^4 x}+\frac {b (A b-2 a B) (a+b x)^{3/2}}{24 a x^5}+\frac {(A b-2 a B) (a+b x)^{5/2}}{12 a x^6}-\frac {A (a+b x)^{7/2}}{7 a x^7}-\frac {5 b^6 (A b-2 a B) \tanh ^{-1}\left (\frac {\sqrt {a+b x}}{\sqrt {a}}\right )}{1024 a^{9/2}} \\ \end{align*}
Time = 0.35 (sec) , antiderivative size = 167, normalized size of antiderivative = 0.72 \[ \int \frac {(a+b x)^{5/2} (A+B x)}{x^8} \, dx=-\frac {\sqrt {a+b x} \left (-105 A b^6 x^6+70 a b^5 x^5 (A+3 B x)-28 a^2 b^4 x^4 (2 A+5 B x)+16 a^3 b^3 x^3 (3 A+7 B x)+512 a^6 (6 A+7 B x)+256 a^5 b x (29 A+35 B x)+32 a^4 b^2 x^2 (148 A+189 B x)\right )}{21504 a^4 x^7}+\frac {5 b^6 (-A b+2 a B) \text {arctanh}\left (\frac {\sqrt {a+b x}}{\sqrt {a}}\right )}{1024 a^{9/2}} \]
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Time = 0.58 (sec) , antiderivative size = 150, normalized size of antiderivative = 0.65
method | result | size |
pseudoelliptic | \(\frac {-\frac {15 b^{6} x^{7} \left (A b -2 B a \right ) \operatorname {arctanh}\left (\frac {\sqrt {b x +a}}{\sqrt {a}}\right )}{8}+\sqrt {b x +a}\, \left (-\frac {928 x b \left (\frac {35 B x}{29}+A \right ) a^{\frac {11}{2}}}{7}+\left (-64 B x -\frac {384 A}{7}\right ) a^{\frac {13}{2}}+x^{2} b^{2} \left (-\frac {5 b^{3} x^{3} \left (3 B x +A \right ) a^{\frac {3}{2}}}{4}+b^{2} x^{2} \left (\frac {5 B x}{2}+A \right ) a^{\frac {5}{2}}-\frac {6 x \left (\frac {7 B x}{3}+A \right ) b \,a^{\frac {7}{2}}}{7}+\left (-108 B x -\frac {592 A}{7}\right ) a^{\frac {9}{2}}+\frac {15 A \sqrt {a}\, b^{4} x^{4}}{8}\right )\right )}{384 a^{\frac {9}{2}} x^{7}}\) | \(150\) |
derivativedivides | \(2 b^{6} \left (-\frac {-\frac {5 \left (A b -2 B a \right ) \left (b x +a \right )^{\frac {13}{2}}}{2048 a^{4}}+\frac {25 \left (A b -2 B a \right ) \left (b x +a \right )^{\frac {11}{2}}}{1536 a^{3}}-\frac {283 \left (A b -2 B a \right ) \left (b x +a \right )^{\frac {9}{2}}}{6144 a^{2}}+\frac {A b \left (b x +a \right )^{\frac {7}{2}}}{14 a}+\left (\frac {283 A b}{6144}-\frac {283 B a}{3072}\right ) \left (b x +a \right )^{\frac {5}{2}}-\frac {25 a \left (A b -2 B a \right ) \left (b x +a \right )^{\frac {3}{2}}}{1536}+\frac {5 a^{2} \left (A b -2 B a \right ) \sqrt {b x +a}}{2048}}{b^{7} x^{7}}-\frac {5 \left (A b -2 B a \right ) \operatorname {arctanh}\left (\frac {\sqrt {b x +a}}{\sqrt {a}}\right )}{2048 a^{\frac {9}{2}}}\right )\) | \(170\) |
default | \(2 b^{6} \left (-\frac {-\frac {5 \left (A b -2 B a \right ) \left (b x +a \right )^{\frac {13}{2}}}{2048 a^{4}}+\frac {25 \left (A b -2 B a \right ) \left (b x +a \right )^{\frac {11}{2}}}{1536 a^{3}}-\frac {283 \left (A b -2 B a \right ) \left (b x +a \right )^{\frac {9}{2}}}{6144 a^{2}}+\frac {A b \left (b x +a \right )^{\frac {7}{2}}}{14 a}+\left (\frac {283 A b}{6144}-\frac {283 B a}{3072}\right ) \left (b x +a \right )^{\frac {5}{2}}-\frac {25 a \left (A b -2 B a \right ) \left (b x +a \right )^{\frac {3}{2}}}{1536}+\frac {5 a^{2} \left (A b -2 B a \right ) \sqrt {b x +a}}{2048}}{b^{7} x^{7}}-\frac {5 \left (A b -2 B a \right ) \operatorname {arctanh}\left (\frac {\sqrt {b x +a}}{\sqrt {a}}\right )}{2048 a^{\frac {9}{2}}}\right )\) | \(170\) |
risch | \(-\frac {\sqrt {b x +a}\, \left (-105 A \,b^{6} x^{6}+210 B a \,b^{5} x^{6}+70 A a \,b^{5} x^{5}-140 B \,a^{2} b^{4} x^{5}-56 A \,a^{2} b^{4} x^{4}+112 B \,a^{3} b^{3} x^{4}+48 A \,a^{3} b^{3} x^{3}+6048 B \,a^{4} b^{2} x^{3}+4736 A \,a^{4} b^{2} x^{2}+8960 B \,a^{5} b \,x^{2}+7424 A \,a^{5} b x +3584 B \,a^{6} x +3072 A \,a^{6}\right )}{21504 x^{7} a^{4}}-\frac {5 b^{6} \left (A b -2 B a \right ) \operatorname {arctanh}\left (\frac {\sqrt {b x +a}}{\sqrt {a}}\right )}{1024 a^{\frac {9}{2}}}\) | \(178\) |
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Time = 0.24 (sec) , antiderivative size = 401, normalized size of antiderivative = 1.73 \[ \int \frac {(a+b x)^{5/2} (A+B x)}{x^8} \, dx=\left [-\frac {105 \, {\left (2 \, B a b^{6} - A b^{7}\right )} \sqrt {a} x^{7} \log \left (\frac {b x - 2 \, \sqrt {b x + a} \sqrt {a} + 2 \, a}{x}\right ) + 2 \, {\left (3072 \, A a^{7} + 105 \, {\left (2 \, B a^{2} b^{5} - A a b^{6}\right )} x^{6} - 70 \, {\left (2 \, B a^{3} b^{4} - A a^{2} b^{5}\right )} x^{5} + 56 \, {\left (2 \, B a^{4} b^{3} - A a^{3} b^{4}\right )} x^{4} + 48 \, {\left (126 \, B a^{5} b^{2} + A a^{4} b^{3}\right )} x^{3} + 128 \, {\left (70 \, B a^{6} b + 37 \, A a^{5} b^{2}\right )} x^{2} + 256 \, {\left (14 \, B a^{7} + 29 \, A a^{6} b\right )} x\right )} \sqrt {b x + a}}{43008 \, a^{5} x^{7}}, -\frac {105 \, {\left (2 \, B a b^{6} - A b^{7}\right )} \sqrt {-a} x^{7} \arctan \left (\frac {\sqrt {b x + a} \sqrt {-a}}{a}\right ) + {\left (3072 \, A a^{7} + 105 \, {\left (2 \, B a^{2} b^{5} - A a b^{6}\right )} x^{6} - 70 \, {\left (2 \, B a^{3} b^{4} - A a^{2} b^{5}\right )} x^{5} + 56 \, {\left (2 \, B a^{4} b^{3} - A a^{3} b^{4}\right )} x^{4} + 48 \, {\left (126 \, B a^{5} b^{2} + A a^{4} b^{3}\right )} x^{3} + 128 \, {\left (70 \, B a^{6} b + 37 \, A a^{5} b^{2}\right )} x^{2} + 256 \, {\left (14 \, B a^{7} + 29 \, A a^{6} b\right )} x\right )} \sqrt {b x + a}}{21504 \, a^{5} x^{7}}\right ] \]
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Timed out. \[ \int \frac {(a+b x)^{5/2} (A+B x)}{x^8} \, dx=\text {Timed out} \]
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Time = 0.29 (sec) , antiderivative size = 296, normalized size of antiderivative = 1.28 \[ \int \frac {(a+b x)^{5/2} (A+B x)}{x^8} \, dx=-\frac {1}{43008} \, b^{7} {\left (\frac {2 \, {\left (3072 \, {\left (b x + a\right )}^{\frac {7}{2}} A a^{3} b + 105 \, {\left (2 \, B a - A b\right )} {\left (b x + a\right )}^{\frac {13}{2}} - 700 \, {\left (2 \, B a^{2} - A a b\right )} {\left (b x + a\right )}^{\frac {11}{2}} + 1981 \, {\left (2 \, B a^{3} - A a^{2} b\right )} {\left (b x + a\right )}^{\frac {9}{2}} - 1981 \, {\left (2 \, B a^{5} - A a^{4} b\right )} {\left (b x + a\right )}^{\frac {5}{2}} + 700 \, {\left (2 \, B a^{6} - A a^{5} b\right )} {\left (b x + a\right )}^{\frac {3}{2}} - 105 \, {\left (2 \, B a^{7} - A a^{6} b\right )} \sqrt {b x + a}\right )}}{{\left (b x + a\right )}^{7} a^{4} b - 7 \, {\left (b x + a\right )}^{6} a^{5} b + 21 \, {\left (b x + a\right )}^{5} a^{6} b - 35 \, {\left (b x + a\right )}^{4} a^{7} b + 35 \, {\left (b x + a\right )}^{3} a^{8} b - 21 \, {\left (b x + a\right )}^{2} a^{9} b + 7 \, {\left (b x + a\right )} a^{10} b - a^{11} b} + \frac {105 \, {\left (2 \, B a - A b\right )} \log \left (\frac {\sqrt {b x + a} - \sqrt {a}}{\sqrt {b x + a} + \sqrt {a}}\right )}{a^{\frac {9}{2}} b}\right )} \]
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Time = 0.29 (sec) , antiderivative size = 256, normalized size of antiderivative = 1.10 \[ \int \frac {(a+b x)^{5/2} (A+B x)}{x^8} \, dx=-\frac {\frac {105 \, {\left (2 \, B a b^{7} - A b^{8}\right )} \arctan \left (\frac {\sqrt {b x + a}}{\sqrt {-a}}\right )}{\sqrt {-a} a^{4}} + \frac {210 \, {\left (b x + a\right )}^{\frac {13}{2}} B a b^{7} - 1400 \, {\left (b x + a\right )}^{\frac {11}{2}} B a^{2} b^{7} + 3962 \, {\left (b x + a\right )}^{\frac {9}{2}} B a^{3} b^{7} - 3962 \, {\left (b x + a\right )}^{\frac {5}{2}} B a^{5} b^{7} + 1400 \, {\left (b x + a\right )}^{\frac {3}{2}} B a^{6} b^{7} - 210 \, \sqrt {b x + a} B a^{7} b^{7} - 105 \, {\left (b x + a\right )}^{\frac {13}{2}} A b^{8} + 700 \, {\left (b x + a\right )}^{\frac {11}{2}} A a b^{8} - 1981 \, {\left (b x + a\right )}^{\frac {9}{2}} A a^{2} b^{8} + 3072 \, {\left (b x + a\right )}^{\frac {7}{2}} A a^{3} b^{8} + 1981 \, {\left (b x + a\right )}^{\frac {5}{2}} A a^{4} b^{8} - 700 \, {\left (b x + a\right )}^{\frac {3}{2}} A a^{5} b^{8} + 105 \, \sqrt {b x + a} A a^{6} b^{8}}{a^{4} b^{7} x^{7}}}{21504 \, b} \]
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Time = 0.13 (sec) , antiderivative size = 279, normalized size of antiderivative = 1.20 \[ \int \frac {(a+b x)^{5/2} (A+B x)}{x^8} \, dx=\frac {\left (\frac {283\,A\,b^7}{3072}-\frac {283\,B\,a\,b^6}{1536}\right )\,{\left (a+b\,x\right )}^{5/2}+\left (\frac {5\,A\,a^2\,b^7}{1024}-\frac {5\,B\,a^3\,b^6}{512}\right )\,\sqrt {a+b\,x}+\left (\frac {25\,B\,a^2\,b^6}{384}-\frac {25\,A\,a\,b^7}{768}\right )\,{\left (a+b\,x\right )}^{3/2}-\frac {283\,\left (A\,b^7-2\,B\,a\,b^6\right )\,{\left (a+b\,x\right )}^{9/2}}{3072\,a^2}+\frac {25\,\left (A\,b^7-2\,B\,a\,b^6\right )\,{\left (a+b\,x\right )}^{11/2}}{768\,a^3}-\frac {5\,\left (A\,b^7-2\,B\,a\,b^6\right )\,{\left (a+b\,x\right )}^{13/2}}{1024\,a^4}+\frac {A\,b^7\,{\left (a+b\,x\right )}^{7/2}}{7\,a}}{7\,a\,{\left (a+b\,x\right )}^6-7\,a^6\,\left (a+b\,x\right )-{\left (a+b\,x\right )}^7-21\,a^2\,{\left (a+b\,x\right )}^5+35\,a^3\,{\left (a+b\,x\right )}^4-35\,a^4\,{\left (a+b\,x\right )}^3+21\,a^5\,{\left (a+b\,x\right )}^2+a^7}-\frac {5\,b^6\,\mathrm {atanh}\left (\frac {\sqrt {a+b\,x}}{\sqrt {a}}\right )\,\left (A\,b-2\,B\,a\right )}{1024\,a^{9/2}} \]
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